# Line slope calculator x-4y=-20

**Straight line given by points A[0; 5] and B[4; 6]**

## Calculation:

**Slope-intercept form of line:**y = 0.25x+5

**Canonical form of the line equation:**x-4y+20 = 0

**Parametric form of the line equation:**

x = 4t

y = t+5 ; t ∈ R

**Slope:**m = 0.25

**Slope angle of line: φ =**14°2'10″ = 0.245 rad

**X intercept:**x

_{0}= -20

**Y intercept:**y

_{0}= q = 5

**Distance line from the origin:**d

_{0}= 4.8507

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(4; 1)

**Normal vector: n =**(1; -4)

**Midpoint of the segment AB: M =**[2; 5.5]

**Perpendicular Bisector equation:**4x+y-13.5 = 0

**Vector OA = (0; 5) ; |OA| = 5**

**Vector OB = (4; 6) ; |OB| = 7.2111**

**Scalar product OA .OB = 30**

**Angle ∠ AOB = 33°41'24″ = 0.588 rad**